For H2O (unboiled):
Narrow pH range = 5.5
[H+] = 10-5.5 = 3.16 x 10-6 M
[OH-] = 10-14 / [H+] = 10-14 / 3.16 x 10-6 = 3.16 x 10-9 M
The complete table is shown below for all solutions following the same procedure:
![pH WideNarrow range| range Acidic/Neutral Solution [H, M[OH], M /Basic H20 (unboiled4 H20 (boiled) Nacl NaAc NH4CI ZnC12 KAl(](http://img.homeworklib.com/questions/0360f1f0-cd36-11ea-b6d3-730fcb3db68c.png?x-oss-process=image/resize,w_560)
From narrow range pH values. Use [H^+] = 10^-pH; **Use K_w = [H^+][OH] = 1.0 times...
pH- Solution [HⓇ]/M* [OH J/M** Wide Range Narrow Range Paper Acidic, basic or neutral H20 (unboiled) H20 (boiled) NaCl a Motoci NaAc NH4Cl 5.0 acidic 5.0 acidic 5.0 acidic 6.5 acidic 9 4.5 acidic 7 5.0 acidic 12.5 basic 12.5 basic ZnCl2 KAI(SO4)2 Na2CO3 1 14 *From narrow range pH value. Use [H"] = 10: Usde K, = Use [H (OH) = 1.0 x 10
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