Question

Mercury is added to a cylindrical container to a depth d and then the rest of the cylinder is filled with water. If the cylinder is 0.7 m tall and the pressure at the bottom is 1.2 atmospheres, determine the depth of the mercury. (Assume the density of mercury to be 1.36 times 10^4 kg/m^3.) m

Answer 1

prerssure at the bottom of the water is P2 = P1+(rho_w*g*(0.7-d))

P2 = 1.013*10^5 +(1000*9.8*(0.7-d))

pressure at the bottom of the mercury is P

P = P2 + (rho_hg*g*d)

P = 1.013*10^5 +(1000*9.8*(0.7-d)) + (rho_hg*g*d)

1.2*1.013*10^5 = 1.013*10^5 +(1000*9.8*(0.7-d)) + (1.36*10^4*9.8*d)

0.2*1.013*10^5 = (6860 - 9800*d + 133280*d)

d = 0.108 m