Question

please use c ++ language and write the comment too. thanks

Pointer Arithmetic

Write a function that passes an array address to a function as a pointer. Using pointer arithmetic, the function determines the average, high, and low value of the array. Your function should have this header: void pointerArithmetic(int *array, int size, double &average, int &high, int &low) Parameter size is the number of elements in array. You may not use the subscript notation [] inside your function – instead, use pointer arithmetic. Write a main program to demonstrate this function.

Answer 1

#include <iostream>
using  namespace std;

void pointerArithmetic(int *array, int size, double &average, int &high, int &low) {
    int sum = 0; //a temporary variable in which sum of all element of array will we kept
                    //and after that average will be calculated as sum / size;
    //PROGRAM LOGIC
    // we will iterate whole array and find the total sum
    //by doing so we will also try to find what is highest value and what is lowest value alongside

    // How we will find highest value ?
    //      - we will compare each element of array with highest
    //      -if any array element is higher then current high, then that element is our new highest
    //      but what will be our initial value of high ( because c++ compiler initialise every variable
    //      with some random data)
    //      if random data is higher then all element of array then we will never find the highest
    //example - {10,20,30,40} is our array and let initial value of high = 132656565 ( some random value)
    //then our program code will go to first array element 10 and comapre it with current high 132656565
    //and found that element is lower
    //similarly for 2nd
    //and third
    //and fourth
    //and last it will return 132656565 as high

    // similarly we can find low
    //So my suggestion is to always initialise a variable with some initially value before using them
    //also u can do the same problem with other many way


    //let's go as i mentioned above


    // in this question we are not allowed to use [] operator
    // this can be achieved by pointer arithematic as
    // a[10] is same as *(a + 10)
    // a[0] is same as *(a)  or *(a + 0)

    for(int i=0;i<size;++i){
        sum += *(array + i);    //finding sum

        if(high < *(array + i)){    //finding high
            high = *(array + i);
        }

        if(low > *(array + i)){ //finding low
            low = *(array + i);
        }
    }

    average = sum * (1.0) / size;

    //NOTE sum * 1.0 will convert the int sum to a double type
}

int main() {
    int arr[10] = {10,20,30,40,50,6,0,145,15};
    double average = 0;
    int high = -1212122;
    int low  = 4152121;
    //NOTE : above are initialised with that date which should not present as element of array

    //calling function
    pointerArithmetic(arr,10,average,high,low);

    cout<<"high    = "<<high<<endl;
    cout<<"low     = "<<low<<endl;
    cout<<"average = "<<average<<endl;
    return 0;
}

//Sample output

Run CPROJECT C:\Users\VIREN CLionProjects\CPROJECT\cmake-build-debug CPROJECT.exe high 145 average = 31.6 Process finished with exit code 0 11