Question

Pointer arithmetic:

a) Write a printString function that prints a string (char-by-char) using pointer arithmetics and dereferencing.
b) Write a function “void computeMinMax(double arr[], int length, double * min, double * max)” that finds the minimum and the maximum values in an array and stores the result in min and max. You are only allowed to use a single for loop in the function (no while loops). Find both the min and the max using the same for loop. Remember to initialize min and max to “good” values.

The function prototypes and a sample main are provided below:

void printString(char str[]);
void computeMinMax(double arr[],int length,double * min,double * max);

void main(){
char s[ ] = "I like homework";
printString(s);
printf("\n");
double arr[] = {1,-1.1,40,50,3,3,2,3};
double min,max;
computeMinMax(arr,8,&min,&max);
printf("min: %lf max: %lf\n",min,max);
}

Answer 1

#include <stdio.h>

void printString(char str[]);
void computeMinMax(double arr[],int length,double * min,double * max);

void main(){
    char s[ ] = "I like homework";
    printString(s);
    printf("\n");
    double arr[] = {1,-1.1,40,50,3,3,2,3};
    double min,max;
    computeMinMax(arr,8,&min,&max);
    printf("min: %lf max: %lf\n",min,max);
}

void printString(char str[]){
    int i = 0;
    char *p = str;
    while(*(p)!='\0'){
        printf("%c",*p);
        p=p+1;
    }
}

void computeMinMax(double arr[],int length,double * min,double * max){
    int minValue = arr[0], maxValue = arr[0];
    for(int i = 1;i<length;i++){
        if(maxValue < arr[i]){
            maxValue = arr[i];
        }
        if(minValue > arr[i]){
            minValue = arr[i];
        }
    }
    *min = minValue;
    *max = maxValue;
}

Note: Please comment below if you have any doubts. upuote the solution if it helped. Thanks!