Question

***Please complete the code in C***

Write a program testArray.c to initialize an array by getting user's input. Then it prints out the minimum, maximum and average of this array. The framework of testArrav.c has been given like below Sample output: Enter 6 numbers: 11 12 4 90 1-1 Min:-1 Max:90 Average:19.50 #include<stdio.h> // Write the declaration of function processArray int main) I int arrI6]i int min-0,max-0 double avg=0; * Write the statements to get user's input and initialize the array zt-Write the statement to call processAr ray print f ("Min : %d Max : %d Avg :8.21f\n", /* Write the corresponding expressions / return Qi void processArray(int arr [],int n, int * Write the statements to calculate min, max and average/ min, int"max, double avg){

Answer 1

#include <stdio.h> void processArray(int arr,int n, int *min, int *max, double avg) //function declaration int main) ( int arr[61; int min-, max-0,i; double avg=0; printf ("Enter 6 Numbers: for ( 1 0;1C6;i++) get user's input and initialize array scanf ( "%d", &arr [1] ) ; processArray (arr, 6, &min, &max, &avg) // call to processArray printf ( "Min: %d Max : %d Average: % . 2LE\n" , min, max, avg) ; void processArray (int arr[, int n, int *min, int max, double avg)f int i; for (i-0:i<n:i++) if (*min>arr [i]) I/ if min is greater then update it if (max<arr[i) /if max is smaller then update it 太avg-arr [ 1]; // āvg 3tores the sum of ārrāy elemen七3 *min-arr[i: max-arr[i] avg/n; // calculate average by dividing it by number of elements in arra

Enter 6 Numbers: 11 12 4 90 1-1 Min:-1 Max:9e Average:19.50 Process returned 28 (0x1C) execution time 12.81e s Press any key to continue