Homework Answers
Parents are: PpYyRr × Ppyyrr
Here the number of gametes produces hy PpYyRr is (2) ^n=(2) ^3=8
(n= is the number of genes in heterozygous form. Here nis 3)
The number of gametes by Ppyyrr is(2) ^n= (2) ^1=2
(Here n is 1)
Punnet square:
| Gametes | Pyr | pyr |
| PYR | PPYyRr | PpYyRr |
| PyR | PPyyRr | PpyyRr |
| Pyr | PPyyrr (*) | Ppyyrr(*) |
| PYr | PPYyrr | PpYyrr |
| pyr | Ppyyrr(*) | ppyyrr(*) |
| pYR | PpYyRr | ppYyRr |
| pYr | PpYyrr | ppYyrr(*) |
| pyR | PpyyRr | ppyyRr(*) |
The offsprings whice are atleast two gene recessive are 6 on number out of 16 offsprings.
Probability is 6/16= 3/8= 0.375
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