
Each breakdown of a graphic plotter table at Airbus Industries costs
$ 50$50.
Following is the historical breakdown distribution:
|
Number of breakdowns |
0 |
1 |
2 |
3 |
4 |
|
Daily breakdown probability |
0.120.12 |
0.210.21 |
0.390.39 |
0.190.19 |
0.090.09 |
For Airbus Industries, the expected daily breakdown cost =
nothing
dollars per day (round your response to two decimal places).
Expected number of breakdown = sum of ( Number of breakdowns* Daily breakdown probability)
= 0*0.12+ 1*0.21+ 2*0.39+3*0.19+ 4*.09
=1.92
Cost of one breakdown $50
So cost of breakdown - expected breakdown * cost of one breakdown= 50*1.92 = $96
Each breakdown of a graphic plotter table at Airbus Industries costs $ 50$50. Following is the...
The partially completed table gives the probability distribution for the number of breakdowns per week for a machine, based on historical data. Breakdowns per week 0 1 2 3 4 or more Probability ? 0.26 0.19 0.09 0.01 Determine the probability that the number of breakdowns in a given week is at most one. (2 decimal places)
The table below shows the daily costs of Cathy's Corn Stand. Cathy sells her corn cobs in a perfectly competitive market. Cathy's Corn Stand's Production Costs Quantity (corn cobs) AVC (dollars) 10.00 $2.50 20.00 2.25 30.00 2.00 40.00 1.81 50.00 1.70 60.00 1.67 70.00 1.68 80.00 1.75 90.00 ATC (dollars) $5.00 3.50 2.83 2.44 2.20 2.08 2.04 2.06 2.14 MC (dollars $2.50 2.00 1.50 1.25 1.25 1.50 1.75 2.25 2.75 a. Draw Cathy's marginal cost (MC) curve. Instructions: Use the...
The table below shows the daily costs of Cathy's Corn Stand. Cathy sells her corn cobs in a perfectly competitive market. MC (dollars) $2.50 5.00 Cathy's Corn Stand's Production Costs Quantity (corn cobs) AVC (dollars) 8.0 $5.00 0 11. 4 .55 13.0 4.62 14.8 4.75 16.3 4.91 17.7 5.10 18.9 5.29 5.51 ATC (dollars) $12.50 10.00 9.23 8.81 8. 59 8.50 8.47 8.52 6 .45 7.41 9.52 Instructions: In part a, round your answer to one decimal place. In part...
The following table contains the probability distribution for the number of traffic accidents daily in a smal town. Complete parts (a) and (b) to the right. a. Compute the mean number of accidents per day. Number of Accidents Px) (Type an integer or a decimal.) Daily (X) 0.22 0.25 0.21 0.11 0.09 0.07 0.05 b. Compute the standard deviation. (Type an integer or decimal rounded to three decimal places as needed.)
One mechanic services 8 drilling machines for a steel plate manufacturer. Machines break down on an average of once every 8 working days, and breakdowns tend to follow a Poisson distribution. The mechanic can handle an average of one repair job per day. Repairs follow a negative exponential distribution. a) On the average, how many machines are waiting for service? The average number of machines waiting for service is _. (Round your response to three decimal places.) b) On the...
One mechanic services 7 drilling machines for a steel plate manufacturer. Machines break down on an average of once every 3 working days, and breakdowns tend to follow a Poisson distribution. The mechanic can handle an average of three repair jobs per day. Repairs follow a negative exponential distribution. a) On the average, how many machines are waiting for service? The average number of machines waiting for service is __. (Round your response to three decimal places.) b) On the...
The table below shows the daily costs of Cathy's Corn Stand. Cathy sells her corn cobs in a perfectly competitive market. Cathy's Corn Stand's Production Costs Quantity (corn cobs) AVC (dollars) ATC (dollars) MC (dollars) 10.00 $2.50 $5.00 $2.50 20.00 2.25 3.50 2.00 30.00 2.00 2.83 1.50 40.00 1.81 2.44 1.25 50.00 1.70 2.20 1.25 60.00 1.67 2.08 1.50 70.00 1.68 2.04 1.75 80.00 1.75 2.06 2.25 90.00 1.86 2.14 2.75 a. Draw Cathy's marginal cost (MC) curve. Instructions: Use...
You may need to use the appropriate appendix table to answer this question. Television viewing reached a new high when the Nielsen Company reported a mean daily viewing time of 8.35 hours per household.† Use a normal probability distribution with a standard deviation of 2.5 hours to answer the following questions about daily television viewing per household. (a) What is the probability that a household views television between 5 and 11 hours a day? (Round your answer to four decimal...
ou may need to use the appropriate appendix table to answer this question. Suppose that the mean daily viewing time of television is 8.35 hours. Use a normal probability distribution with a standard deviation of 2.5 hours to answer the following questions about daily television viewing per household a.How many hours of television viewing must a household have in order to be in the top 2% of all television viewing households? (Round your answer to two decimal places.) b.What is...
Concept Question 3.15 Question Help The following table shows the daily relationship between the number of workers and output (Q) for a small factory in the short run, with capital held constant. Each worker costs $200 per day, and the firm has fixed costs of $50 per day. Calculate total cost (TC), marginal cost (MC), and average total cost (ATC). (Round your answers to two decimal places.) TC MC ATC Workers 0 1 2 0 0 50 110 176 229...