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For the reaction 4A(g) + 3B(g) rightarrow 2C((g)
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Answer #1

4A(g) + 3B(g) \rightarrow 2C(g)

rate = k [A]n [B]m

Comparing experiment 1 and 3, when concentration [B] is increased by 2 times keeping concentration [A] constant, the initial rate increases by 2 times.

2 rate = k [2B]m

\Rightarrow   2 rate = k  [2B]1

m = 1

So, Reaction order for B is 1.

Again, comparing experiment 3 and 4, when concentration [A] is increased by 3 times keeping concentration [B] constant, the initial rate increases by 9 times.

9 rate = k [3A]n

\Rightarrow 9 rate = k  [3B]2

\Rightarrow n = 2

So, Reaction order for A is 2.

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