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Please explain procedure: A+B-2C The following data are obtained for this reaction at a certain temperature: [A]o (M) 0.150 0.150 0.200 0.300 [B]o (M) 0.250 0.3620 0.400 0.400 initial rate (M/hr) 1.08 x 104 1.56 x 10-4 2.30 x 104 3.44 x 10-4 run # 4 (a) Determine the order of the reaction with respect to A and with respect to B and write the rate expression for the reaction. (answer: first-order with respect to A and first-order with respect to B; rate - (b) Calculate the rate constant for the reaction including its units. (answer: 2.88 x 10-3 M-lhr1) (c) What must [A] be so that the rate of the reaction is 6.40 x 104 mole/L-hr when [B]-0.939 M? (answer: 0.237 M) (d) Use the result of (a) to suggest a likely mechanism for the reaction, i.e. suggest how the reaction actually occurs at the molecular level. (answer: one molecule of A collides with one molecule of B; two molecules of C are formed during the collision)

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Given that [BJ[M] 0.250 0.3620 0.400 0.400 Initial rate (M/h) 1.08 x 10-4 1.56 × 104 2.30 x 10-4 3.44 x 10-4 Exp.[A][M] 1. 2. 3. 4. 0.150 0.150 0.200 0.300 The rate law is Ratek [Alx [Bl y where, x - order of reaction with respect to [A] y- order of reaction with respect to [B] From exp.1 and 2 Al- constant, So rate - k[Bly 1.08 x 10-4-k (0.250)Y From, 1: From.2: Divide eq.2 with eq.1 1.56x10*k(0.3620) 1.08x101k(0.250) 1.444444 (1.448)From Exp. 3 and 4 [B] constant, So rate -k [A]x From. 3 From. 4: 2.30 x 10-4-k (0.200)* 3.44 x 10-4-k (0.300)* Divide eq.4 with eq.3 3.44x10 _k(0.300) 2.30x101 k(0.200)* 1.50 (1.50) (a) Order with respect to A 1 Order with respect to B = 1 The rate law is Rate -k [A] * [B] y k [A] [B1- k [A][B] (b) k-Tate k= [Al[B] From Trail.1, substitute the values, 1.08x104 M.hr1 (0.150M) (0.250M) 0.00288 M.hr-1 k k-2.88x103 M1 hr1rate LALBI LA Tatc kLB 6.40x104 M.hr1 2.88x10 3 M1 hr1x0.939M [A] = 0.23 6658M 14-0.237M [Al 0.237M Since the order with respect to A and B is first order, in the rate determining step, one molecule of A and one molecule of B is involved in the reaction. in the reaction, one molecule of A reacts with one molecule of B When the reaction occur, result in the formation of 2 moles of C.

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