Question

Consider the reaction A + B ? products From the following data obtained at a certain...

Consider the reaction A + B ? products

From the following data obtained at a certain temperature, determine the rate law, the order of the reaction, and calculate the rate constant k.

Experiment 1: [A] = 1.50 M; [B] = 1.50 M; Initial Rate = 3.20 x 10-1 M/s

Experiment 2: [A] = 1.50 M; [B] = 2.50 M; Initial Rate = 3.20 x 10-1 M/s

Experiment 3: [A] = 3.00 M; [B] = 1.50 M; Initial Rate = 6.40 x 10-1 M/s


Please explain to me how you got the answer step by step >< Thank you!

A. Rate = k[A][B]

order of reaction = 2

k = 0.142 s-1

B.Rate = k[A]

order of reaction = 1

k = 0.213 s-1

C. Rate = k[A]2

order of reaction = 2

k = 0.142 s-1

D. Rate = k[B]

order of reaction = 1

k = 0.213 s-1

0 1
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Answer #1
Concepts and reason

Rate of the reaction: Rate is the change in concentration of a reactant or change in the concentration of a product per unit time.

Rate=AIConcentration]
At
Atis the change in time

Rate of a reaction depends on the temperature, pressure, and concentration of the reactant or product. It varies with temperature. In chemical kinetics, only the Arrhenius equation relates to the temperature and rate of the reaction.

The order of the reaction depends upon the n-value, here, n is the sum of the powers of the stoichiometry coefficients.

Rate constant: Rate constant (k) is the proportionality constant of a reaction that is dependent on the temperature.

Rate law expression: The rate law expression is related to the rate of a reaction, the rate constant, and the concentration of the reactant or product.

Fundamentals

Rate law can be expressed as follows:

aА+bВ-
— >сС +dD
rate k[AJ [B

Given that

А + В —>рroduct

Let

Experiments

[A]
M

[B
M

Initial rate M/s

1

1.50 M

1.50 M

3.20x10 M/s

2

1.50 M

2.50 M

3.20x10 M/s

3

3.00 M

1.50 M

6.40x10 M/s

rate k[A[B
.

Taking experiment (1) and (2)

Dividing (1) by (2)

k[A][B]*
k[A[B
3.20x10 M/s [1.50] [1.50]|
3.20*10M/s 1.50] [2.50]*
[1502.50
l= [0.6

Thus b 0

Dividing (1) by (3)

k[A] [B]
k[AJ[BJ
3.20x10 M/s [1.50] [1.50]|
6.40x10 M/s 3.00r [1.50]*
0.5= [0.5]

Thus а 31

Rate k[A] B]J

Rate k[A
--------------------------(1)

Rate of the given reaction doesn’t depend on the concentration of В
therefore the options A and D are incorrect.

А.
Rate k A][B]
order of reaction =2
k 0.142 s

D.
order of reaction =1
Rate k [B]
k 0.213 s

Order of the reaction is not equal to two, therefore the options C, is also incorrect.

С.
Rate kA]
order of reaction = 2
k 0.142 s

Substitute the rate and concentration in rate expression

Rate k[A]
----------------------------(1)

Order of reaction =
1

rate
k
[A]
6.40x10 M/s
3.00M
k 0.213s

Thus the correct option is B

Ans:

The rate law, order and rate constant were identified and highlighted as given below

A. Rate k[A][B],order of reaction-2,k =0.142s.
B.Rate k[A],order of reaction =1,k = 0.213 s1.
C. Rate k[AT,0rder of reaction

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