Question

An unknown gas at 59.1 °C and 1.00 atm has a molar mass of 28.01 g/mol.

Assuming ideal behavior, what is the density of the gas?

Answer 1

PV = nRT No. of moles (n) = weight/ molar mass So; PV - (weight / molar mass) RT P x molar mass = (weight/ volume) x RT So: Density = (P x molar mass)/ RT - (1.0 atm x 28.01 g/mol) (0.0821 L atm mol1 K1 x 332.25 K) = 28.01 / 27.28 = 1.02 g/L