Question

An unknown gas at 55.1 °C and 1.05 atm has a molar mass of 44.10 g/mol.

assuming ideal behavior, what is the density of the gas?

Answer 1

From gas laws; PV = nRT

n = weight / molar mass

PV = (weight / molar mass) RT

P x Molar mass = (weight / Volume) RT

density = weight / Volume.

So;

Density (d) = P x Molar mass / RT = (1.05 atm x 44.10 g/mol) / (0.0821 x 328.25 K) = 1.72 g/L