Please can I have step by step The pH of a solution prepared by mixing 50.0...
Please can I have step by step
The pH of a solution prepared by mixing 50.0 mL of 0.125 M KOH and 50.0 mL of 0.125 M HCl is __________. Answer 7.00
A 25.0 mL sample of an acetic acid solution is titrated with a 0.175 M NaOH solution. The equivalence point is reached when 37.5 mL of the base is added. The concentration of acetic acid is __________ M.
Answer 0.263
Homework Answers
1)
millimoles of KOH = 50 x 0.125 = 6.25
millimoles of HCl = 50 x 0.125 = 6.25
at equivalence point
millimoles of acid = millimoles of base
pH = 7.00
2)
millimoles of NaOH = 0.175 x 37.5 = 6.5625
volume of acetic acid = 25.0 mL
at equivalence point
millimoles of NaOH = millimoles of acetic acid
6.5625 = 25 x M
M = 0.263
concentration of acetic acid = 0.263 M
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