![12. Imagine a cross between AaBb x aabb produces progeny in the following proportions: | AaBb 31 aabb | 33. Aabb | 12 aaBb] 1](http://img.homeworklib.com/questions/d75c87d0-d110-11ea-a30e-53b4e820ddd4.png?x-oss-process=image/resize,w_560)
Homework Answers
Question 12:
Null hypothesis: The genes are not linked. It means independent assortment is occured.
Please look in the image for chi square test:
Now the chi square from experiment (17.195) is more than chi square from table (7.815). That's why null hypothesis is rejected. It means linkage is found between two genes.
Gene A and B are in cis form because parental types offsprings are more than recombinant type offsprings.
The genetic distance between A and B is calculated by recombination great between two genes.
Recombination frequency= ( recombinant/total) ×100
= {(12+13) /(12+13+31+33) }×100= (25/89) ×100=28.08
That's why gene distance between A and B is 28.08 centimorgan.
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