Question

How to call a function in another function?C++ Project assistance. In the Project I am attempting to pass getOutcome into runGame to attempt to figure out who would win. Upon trying I get an error that getOutcome isn't in scop of runGame. The & symbols were my last attempt at trying to pass it, I do see it is wrong, and any help that can help me with just that is very appreciated.

#include <iostream>
#include <fstream>
#include <string>
#include <ctime>

using namespace std ;

void runGame(int gamemode) // DECLARING WHAT KIND OF GAME WILL BE PLAYED
{
string name;

if(gamemode == 1)
{
cout << "Enter a name for Player 1 : " ;
cin >> name ;

int round , oddRound , choice ; // These variables are on the outside of the do loop
// so the "Do-While" will work.
do
{

cout << "Best of how many rounds? ODD ROUNDS ONLY : " ;
cin >> oddRound ;
round = oddRound % 2 ; // check for remainders to see if ODD or EVEN #

if (round != 0 )
{
cout << "Enjoy \n" ;

for(round = 0 ; round < oddRound ; round++) // Game will run for however many times the user requested
{
cout << "Rock (1) , Paper (2) , Scissors (3)? " ; //prompting user for choice
cin >> choice ;
&getOutcome(&choice , &computer) ; //ATTEMPTING to pass the choice to getOutcome

}
}
else if(round == 0)
{
cout << "My guy read! Try again! \n" ;
}

}while(round == 0);
} // END OF GAME MODE 2

void getOutcome(int choice , int computer)
{
int rock, paper, scissors , wins, compWins, losses, compLosses ;
rock = 1;
paper = 2;
scissors = 3;

if((choice == rock && computer == scissors) || (choice == paper && computer == rock) || (choice == scissors && computer == paper))
{
cout << " wins this round! \n " ; //PUT NAME's HERE
wins++;
compLosses++;
}
else if ((choice == scissors && computer == rock)|| (choice == rock && computer == paper) || (choice == paper && computer == scissors))
{
cout << "loses this round! \n " ; //PUT NAME"S HERE
compWins++ ;
losses++;
}
}

Answer 1

In order to call one function inside another function, first you need to define or declare the function which you will be calling in another function, because the c++ compiler follows top-down approach, it start compiling from the top of the program and when it finds some function call, it looks for that function in the above code, if any function gets matched it call that function. You cannot call the function inside another function if you are declaring the called function below the calling function. You need to give the declaration or defination of the called function above the calling function.

For e.g there are two approaches to call one function inside another function :

Suppose you want to call first() inside second(), then you can do this in two ways

1) By declaring and defining the called function above the calling function

void first(){ /* You can change the return type of the function,if you want to get some values returned from the function and change the return type appropriately,here i am using void so i need not to return any value.*/

//statements

}

void second{

first(); //function called within another function

}

2) Second approach is by first declaring the called function above the calling function and then defining it below the calling function.

void first(); //function only declared but not defined

void second(){

first();

}

void first(){ //function defined

//statements

}

/* In your code given,simply add this line below using namespace std */

void getOutcome(int choice , int computer);