Solution)
We know,
Work done is given by,
W = Fscos(theta)
Part a)
W1 = 100*7*cos(0) = + 700 J (Ans)
=======
Part b)
W2 = 50*4*cos(180) = -200 J (Ans)
========
Part c)
Total work,
W = W1 +W2 = 700-200 =500 J (Ans)
======
Problem 6.28 You bring a boat toward the dock by pulling on a rope with a...
Starting from rest, you drag a 30.0 kg box as shown below. Your force is 200.0 N while friction applies a 185 N force. What is the box's speed if you drag it across the ground for 5.00 meters? ______________ m/s With a starting velocity of 2 m/s to the right, you drag a 30.0 kg box for 4 meters, as shown below. Your force is 200.0 N and the box's final velocity is 1.15 m/s to the right. How...
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