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Phys Sci 1.2.23 The relationship between the length of a pendulum L and the time for one complete oscillation can be determin
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as let regression line ŷ = ât in then using least squares method I min s - 20 - 9 2 - 2 2 (y - 2 - 6 mj² == -26%: -20) Imst na)

L(ft) (X) T(sec) (y) X-Xbar y-ybar Sxx Sxy y^
1 1.13 -1.5 -0.58857 -1.5 -0.58857 1.227143
1.5 1.36 -1 -0.35857 -1.5 -0.53786 1.390952
2 1.57 -0.5 -0.14857 -1 -0.29714 1.554762
2.5 1.76 0 0.041429 0 0.103571 1.718571
3 1.92 0.5 0.201429 1.5 0.604286 1.882381
3.5 2.08 1 0.361429 3.5 1.265 2.04619
4 2.21 1.5 0.491429 6 1.965714 2.21
sum 17.5 12.03 6.632857
average 2.5 1.718571
a^ 0.899524
b^ 0.327619

2.5 y = 0.3593x +0.8204 Tisec) T(sec) – Predicted ......... Linear (T(sec)) +o 1 1 2 3 4 5 Lift)

b)

Correlation coefficient b^ = 0.327619

It shows change of rate in T(sec) at one unit change in L(ft)

a)

Least Square line equation

Y = 899524 + 0.327619X

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