Question

Question 14

The enthalpy ( Δ H ) of combustion of C₃H₆ gas is -2058 kJ/mol. 0.985 atm of C₃H₆ gas is combusted with an excess of O₂ gas in a 2.50 L bomb calorimeter at 298.15 K. The heat capacity of the calorimeter is 16.0 kJ/^oC. Calculate the temperature change of the calorimeter (in ^oC).

Answer 1

Pressure Volume Temp p = 0.985 atm v= 2.50 L T = 298.15k and R = 0.082 Latm molik PV = nRT VV Mole of CzH6 = = = 1 R7 0.985 X 2.50 0 0.082 x 298.15 0.1007 mole given AH = -2058 kJ/mole that means 1 mole cat give = 2058 KJ Heat than 0.1007 mole Cat6 give & 0.1007 x 2058 kJ Heal 207,2406 KJ Heat Temperature Change of calorimeture (AT) = – Ccal AT = 207.2406 kJ 12.9525 - 12.95257 16.0, KI ***