Question

Assuming that an enzyme catalyzed reaction follows Michaelis-Menten kinetics with a Km of 1 x 10-6 M. If the initial reaction rate (V0) is 0.1 μmol/min at 0.1 M, what would it be at 0.01 M, 10-3M, and 10-6 M?

Answer 1

constant (km) = Michaelis - Menten 1x100M initial reaction rate (Vol = 0.1 demol min substrate emo - Oijn [s] from Michaelis - Menten tanstant equation Vos Vmax cs] . Km+[s] maximum velocity reaction Vmax= lemol = 10-6 moi Ool mol min = Vmax olm 10 6M + O.IM

0.1 Amol s10 mol los mol mint a Vmax 0.1m 10-M +O.IM 16 mol = Vmax Ourm Vmax= 105 mol min! [s] = 0.01M when Vo= 105 mol minxo.olm 106M + 0.01 M = 10-5 mol min xeoTM = 10-5 mol min? When [s] = 103m los los mol mint x 10 3M 10-6M + 103 1.-5 mol min' xizm - = 165 mol mint ا الیہا when [5]= 106 les W px phile low gol 10-6M + 10-6M = 105 mol min ' x 160 5x10-6 mol min 2 x 166 m