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How much energy is stored by a 14µF capacitor with a potential difference of 400V ?

How much energy is stored by a 14µF capacitor with a potential difference of 400V ?

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Answer #1

Energy Stored:

U=\frac{1}{2}CV^{2}

U=\frac{1}{2}(14X10^{-6})400^{2}

\boldsymbol{U=1.12\: J}

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