A child bounces a 50-gram superball on the sidewalk. The velocity of the superball changes from...
A child bounces a 50-gram superball on the sidewalk. The velocity of the superball changes from 21 m/s downward to 19 m/s upward. If the contact time with the sidewalk is 1/800 s, what is the magnitude and direction of the force exerted on the superball by the sidewalk?
Homework Answers
Force = Change in momentum/Time
Change in momentum = m*(v1-v2) = 5*10^-2* (19 - (-21)) = 2
Time = 1/800
Force = 2/(1/800) = 1600N
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