In a sample, you used 0.5 g of wheat germ in 5 ml of enzyme
extraction buffer (total volume of 5.5 mL). After homogenization
and centrifugation,you used a 250 µl aliquot of the wheat germ
extract to determine the amount of acid phosphatase present. You
found that 3.2 µg of acid phosphatase was present in the 250 µl
aliquot.
First off, what is the concentration of acid phosphatase in your
extract?
How many micrograms of acid phosphatase are present in a gram of wheat germ from your extract?
concentration is B-0.0128 microgram/microlitre.
micrograms of acid phosphatase is A-128


In a sample, you used 0.5 g of wheat germ in 5 ml of enzyme extraction...
You have 0.5 mL sample of protein extract (absorbance 0.5930) with a concentration of 181.2 ug/mL. How many ug (micrograms) of sample do you have?