Question

The number of deaths attributed to UV radiation in African countries in the year 2002 is given in table #3.2.19 ("UV radiation: Burden," 2013). Table #3.2.19: Number of Deaths from UV Radiation 50 84 31 338 6 504 40 7 58 204 15 27 39 1 45 174 98 94 199 9 27 58 356 5 45 5 94 26 171 13 57 138 39 3 171 41 1177 102 123 433 35 40 456 125 a.) Using technology, find the mean and standard deviation. b.) Use Chebyshev’s theorem to find an interval centered about the mean number of deaths from UV radiation in which you would expect at least 75% of the numbers to fall. c.) Use Chebyshev’s theorem to find an interval centered about the mean number of deaths from UV radiation in which you would expect at least 88.9% of the numbers to fall.

Answer 1

a) sample info:

$Standard.deviation:S=205.44$

b)

an interval centred about the mean number of deaths from UV radiation in which you would expect at least 75% of the numbers to fall = $(130.98\pm 2*205.44)=(-279.9,541.86)$

c) k=3

an interval centred about the mean number of deaths from UV radiation in which you would expect at least 88.9% of the numbers to fall. is

$(130.98\pm 3*205.44)=(-485.34,747.3)$