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9. Using B=00, design the circuit shown so that the emitter currents of Q1, Q2, and Q3 are 0.5 mA, 1.0 mA, and 2.0 mA respect

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Given ie-oosma, ie, = ima, svega 2 mg ß is large lezic, o it on 4t5 ↑ 15 pts R & R Ev Porr ņ photos on F bipoll wa Á HMTV 5 Aięy = 0.5 mm, ie,= Ima , lez = 2MA ie, = 0.4966MA, ic, = 0.993ma, i2=1.986 mA V = Vccic, R = 5-(0.496688) = 0.026 V Ny-Ug = 0

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