________ is the oxidizing agent in the reaction below.
Cr2O72- + 6S2O32- + 14H+ → 2Cr3+ + 3S4O62- + 7H2O
Cr2O72- + 6S2O32- + 14H+ → 2Cr3+ + 3S4O62- + 7H2O
Cr2O72- chromium oxidation state is +6
chromium oxidation sate +6 to +3 decreaction . So this reaction is reduction reaction
Cr2O72- --------> 2Cr+3 reduction reaction
A substance which participate in reduction reaction is called oxidizing agent.
Cr2O72- is oxidizing agent. >>>>> answer
________ is the oxidizing agent in the reaction below. Cr2O72- + 6S2O32- + 14H+ → 2Cr3+...
Part E Calculate the standard cell potential for Cr2O72−(aq)+6Fe2+(aq)+14H+(aq)→2Cr3+(aq)+6Fe3+(aq)+7H2O(l) Express your answer using two decimal places. Part F Calculate the standard free-energy change for Cr2O72−(aq)+6Fe2+(aq)+14H+(aq)→2Cr3+(aq)+6Fe3+(aq)+7H2O(l) Express your answer as a whole number.
For the reaction, shown below, determine which statements are True and which are False. 3Fe(s) + Cr2O72-(aq) +14H+(aq) → 3Fe2+(aq) + 2Cr3+(aq) + 7H2O(l) ξo=1.77V 1. The reducing agent is dichromate (Cr2O72-). 2. The oxidation state of chromium in dichromate is +3. 3. The oxidation state of hydrogen changes from 0 to +1. 4. The highest oxidation state for oxygen in this reaction is 0 5. The oxidizing agent is Fe2+ (aq) 6. The chromium half-reaction takes place in an...
is oxidized in the following reaction: Cr2O42- + 652032- + 14H+ + 2Cr3+ + 354062- + 7H20 Select one: O a. Cr6+ O b.52+ O c. H+ O d. 02- O e. S4062- __ is the reducing agent in the reaction below. Cr20-2- + 6S2O32- + 14H+ + 2Cr3+ + 354062- + 7H2O Select one: O a. Cr20-2- O b. S2O32- O c. H+ O d. Cr3+ o e. S4062- 0
What is the role of hydrogen in these two reactions? 3 Sn2+ + Cr2O72- + 14H+ --> 3 Sn4+ + 2Cr3+ + 7H2O 5 Fe2+ + KMnO4- + 8H+ --> 5 Fe3+ + Mn2+ + 4H2O I am asking because it is part of the overall balanced equation but it has the same oxidation number on both sides of the reaction. This goes beyond just balancing the atoms in the reaction, so please don't answer that! Can anyone please explain?...
Which substance is the reducing agent in this reaction? Cr2O72−+3HNO2+5H+→2Cr3++3NO3−+4H2O Express your answer as a chemical formula.
Could someone please explain how to do this question?
Thanks!
Select the balanced equation for the reaction of K2Cr2O7 and FeSO4 in an acidic aqueous solution: o a. 2 Select one: a. Cr20-2- +6Fe2+ = 2Cr3+ + 6Fe3+ b. 14H+ + Cr2O72- + 6Fe2+ → 2Cr3+ + 7H2O + 6Fe3+ c. 7H2+ + Cr20-2- + 6Fe2+ → 2Cr3+ + 7H2O + 6Fe3+ d. 14H+ + 2Cr20-2- + 6Fe2+ → 2Cr3+ + 7H2O + 6Fe3+ O e. 7H+ + Cr2O72- +...
1. (6 pts.) Given below is the standard reduction potential for Cr2O72. in 1.0 M acid: Cr2O72- + 6 Fe2+ + 14H+ 2Cr + + 6 Fe3+ + 7H0 E=0.56 V) Is Cr07 a stronger oxidizing agent in acid, base or neutral solution? Explain.
Choose the label which best describes the following:
A B C D E F G H Direction which anions move through the
salt bridge
A B C D E F G H Pt anode
The overall, balanced, spontaneous reaction occurring in this
(standard) cell is:
Cr2O72−(aq) + 6Cl−(aq)
+ 14H+(aq) → 7H2O(l) + 2Cr3+(aq) +
3Cl2(g)
7H2O(l) + 2Cr3+(aq) + 3Cl2(g) →
Cr2O72−(aq) + 6Cl−(aq)
+ 14H+(aq)
7H2O(l) + 2Cr3+(aq) + Cl2(g) →
Cr2O72−(aq) + 2Cl−(aq)
+ 14H+(aq)
2Cr3+(aq) + 3Cl2(g) →...
Identify the species oxidized, the species reduced, the oxidizing agent and the reducing agent in the following electron transfer reaction. 2Cr3+ + 3712Cr + 3Zn2+ species oxidized species reduced oxidizing agent reducing agent As the reaction proceeds, electrons are transferred from Identify the species oxidized, the species reduced the oxidizing agent and the reducing agent in the following electron transfer reaction. Hg2+ + SnHg+Sn2+ species oxidized species reduced oxidizing agent reducing agent As the reaction proceeds, electrons are transferred from
Consider the following balanced cell reaction: Cr2O72- + 14H+ + 6I- ⟶ 2Cr3+ + 3I2+ 7H2O In the determination of the cell potential at nonstandard conditions, the value that should be used for “n” (i.e. number of electrons transferred) in the Nernst equation is: A. 2 B. 6 C. 1 D. 4 E. 5