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estion 6 of 8 A mixture of 186.8 g of Cl, and 40.8 g of Preacts completely to form PC1, and PCI. Find the mass of PCl, produc
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Answer #1

The bakanced reaction is: 2P + 4Cl2 ----> PCl3 + PCl5

Molar mass of P = 31g/mol and Molar Mass of Cl2 = 71g/mol

Given data: Mass of P = 40.8g and Mass of Cl2 = 186.8g

Moles of P = 40.8g / (31g/mol) = 1.316 mol

Moles of Cl2 = 186.8g / (71g/mol) = 2.631 mol

Moles of P/ Coeff. of P = 1.316 / 2 = 0.658

Moles of Cl2 / Coeff. of Cl2 = 2.631 / 4 = 0.6577

Moles of Cl2 / Coeff. of Cl2 is less so Cl2 is limiting reagent.

As Coefficient of PCl5 is also 1. So Moles of PCl5 formed = Moles of Cl2 / Coeff. of Cl2 = 0.6577 mol.

Molar mass of PCl5 = 208.5g/mol.

Mass of PCl5 produced = 0.6577mol × 208.5g/mol = 137.14 g

Hemce Mass of PCl5 produced is 137.14g

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