Question

What is the magnitude of the electric field between two air-filled rectangular plates that are 70.8 cm by 64.6 cm with +0.23
0 0
Add a comment Improve this question Transcribed image text
Answer #1

Solution Aree of rectangular plate A = (40.8 cm) (64.6) Cm F A = 45 73.68 (2 OR A: 04573682 AV = End A: UD E. EA re: 0.23nc E

Add a comment
Know the answer?
Add Answer to:
What is the magnitude of the electric field between two air-filled rectangular plates that are 70.8...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated...

    An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated by a distance of 2.20 mm. If a 21.2-V potential difference is applied to these plates, calculate the following. (a) the electric field between the plates magnitude kV/m direction (b) the capacitance pF (c) the charge on each plate pC

  • An air-filled capacitor consists of two parallel plates, each with an area of 7.6 cm2, separated...

    An air-filled capacitor consists of two parallel plates, each with an area of 7.6 cm2, separated by a distance of (a ) If a 15.0 V potential difference is applied to these plates, calculate the electric field between the plates. (b) What is the surface charge density? (c) What is the capacitance? (d) Find the charge on each plate. kV/m nC/m2

  • An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated...

    An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated by a distance of 1.70 mm. A 25.0-V potential difference is applied to these plates. (a) Calculate the electric field between the plates. kV/m (b) Calculate the surface charge density. nC/m2 (c) Calculate the capacitance. pF (d) Calculate the charge on each plate. pC

  • An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated...

    An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated by a distance of 2.10 mm. A 25.0-V potential difference is applied to these plates (a) Calculate the electric field between the plates kV/m (b) Calculate the surface charge density. nc/m2 (c) Calculate the capacitance. pF (d) Calculate the charge on each plate pc

  • The electric field between the two plates shown below has a magnitude of 570 N/C. The...

    The electric field between the two plates shown below has a magnitude of 570 N/C. The plates are separated by a distance d of 2.8 cm. What is the magnitude of the potential difference Δ VBA between the two plates (in V)? What is the speed of a proton (in m/s) released from rest very close to plate A just before it hits plate B? (Enter the magnitudes.) (Assume that the system is in a vacuum and the surface area...

  • An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated...

    An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated by a distance of 1.80 mm. If a 17.0 V potential difference is applied to these plates, calculate the following. (a) the electric field between the plates _______ kV/m (b) the capacitance _______ pF (c) the charge on each plate _______ pC

  • Problem l: (5 marks) An electric field is set up between two parallel plates, each of...

    Problem l: (5 marks) An electric field is set up between two parallel plates, each of area A-20 m, by putting 0-1.0 HC of charge on one plate and-Q=-L0pCofchargean the other. The plates are separated by d 0mm with their centers opposite each other, and the charges are distributed uniformly over the suface of the plates 1) What is the magnitude of the electric field between the plates at a distance of 1.0 mm from the positive plate? (1.5 marks)...

  • A parallel-plate air-filled capacitor having area 57 cm2 and plate spacing 1.4 mm is charged to...

    A parallel-plate air-filled capacitor having area 57 cm2 and plate spacing 1.4 mm is charged to a potential difference of 820 V. Find (a) the capacitance, (b) the magnitude of the charge on each plate, (c) the stored energy, (d) the electric field between the plates, (e) the energy density between the plates.

  • A parallel-plate air-filled capacitor having area 42.0 cm2 and plate spacing 1.10 mm is charged to...

    A parallel-plate air-filled capacitor having area 42.0 cm2 and plate spacing 1.10 mm is charged to a potential difference of 570 V. Find (a) the capacitance, (b) the magnitude of the charge on each plate, (c) the stored energy, (d) the electric field between the plates, (e) the energy density between the plates.

  • A parallel-plate capacitor has the volume between its plates filled with plastic with dielectric constant K....

    A parallel-plate capacitor has the volume between its plates filled with plastic with dielectric constant K. The magnitude of the charge on each plate is Q. Each plate has area A, and the distance between the plates is d. Use Gauss's law to calculate the magnitude of the electric field in the dielectric. Express your answer in terms of the given quantities and appropriate constants. Use the electric field determined in part A to calculate the potential difference between the...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT