Question

Question #1 10 marks Draw a simple hydraulic Circuit which will operate a hydraulic cylinder of a machine. The load during forward stroke is 15 KN and that during return stroke is approximately 9.5 KN. The forward and return speeds are about 3.5 m/min and 5.5 m/min respectively. The total stroke of the cylinder is 400 mm. A provision is required to hold the cylinder anywhere in between the end positions. Select the different components from the data tables given. Specify the ratings of the components in case, it is not available in the given data. Save Passage before moving to next question. Passage word limit: 500 words File size limit: 2 MB (JPG) Save Passage Select file Select file Select file Select file

DATA FOR THE QUESTION IS :

Answer 1

Detailed answer of above asked question is solved as below.

→ Hydraulic circuit to operate cylinder. - melon out arcuit is chosen to adjust the speed of extension & retraction as per requirement - It has two low control valves, F. 4 F2 Fi is used to control speed of extension Ez is used to control speed of retraction F & fix w mis Given Fe = loud during extension = 15 km FR = load during retraction= g. 5 kN Ve="V = velocity during extension & retraction 3.5mmin 40 55 mimin = 0.05833 mis, to 0.09161 t = stroke = .400 mm = 0.4m. a Design From given table of vane pump, it is seen that the pumps are. avollable for a maximum pressure of mo bar, Honce let us start the design of cylinder assuming pressure as to bara 17 selection of cylinder. a) During extension stroke Door of cylinder =D= are 14x15000 -0.05223 ma 52.233 mm TX MONIOS b) During retraction stroke effective dramelera De = 102-dz = 489500 = 0.04156m Тf P TX TOXIOU = 41.568 mm From the table of cylinder Aa is selected It has bove drameter D= 115mm = o orism rod diameter d: 45 mm = 0.045m. 2) selection of pump a) pressure during extension : pez 4 Fe Lax 15000 A TX 100052 Pe= 33.958105 N/m2 = 33.95 bar. V TP TTD2

0 15.4616 4 FR 4x950 b) Discharge during extension Qe: AxVea II DPx ve ons? x 005889 to 0:-093? x 0-091667 2.546 98104 to 4.049410-4 mals 'to 24.29g1 ats/min c) Pressure during refracron = PRO FR (A-a) TT CD ² d 2) (0.0175 0.04 52) 33.59x105 N/m2 = 39.59 bar. d) Discharge during retration Qp = (A-Q) YR = IT CD2-d2) (oetse ou 4 g2) 0-05839 to my rooms 2.0045")*0:09149 1.6492x10-4 to 2.5.915 x 10 4 mols 9.8954 ets/min discharge required is. 24.299) ets/men ad 33.95 bar. during extension 4 15:55) its) min at 33-59 bar during refraction from given vane pump, .pump Ps is selected, it has discharge. 39 etsimin at o baire 37.5 ets/min at 35 bar, 35.6 lbs/min at robar - selection of reservorm. capacity of reservoin should be more than three time the maximum discharge, capacity of reservoir 73437.5 > 112.5 efsimine so reservoir moder Tois selected, have capacity 250 ets 4) selection of other component. Max. pressure in system = 33.95 bar, nordice Max Discharge in system: 24.29g1 etsimin to - so

For these above value, following components are selected sr No Flow rate range. component strainer. 2 3 Pressure gauge Relief valve 4 flow control valve. Direction control valve cheek valve Model Pressure range s, 38 ets/min. PG 6.40 bar. R3 Tobari 30°4 ets/min F4 no bar 0-24 6 ets/min 210 bar 38 ets/min 210 bar 30.4 ets/min. ets/min = dpm 5 C2