Question

Question #1 10 marks Draw a simple hydraulic Circuit which will operate a hydraulic cylinder of a machine. The load during forward stroke is 15 KN and that during return stroke is approximately 9.5 KN. The forward and return speeds are about 3.5 m/min and 5.5 m/min respectively. The total stroke of the cylinder is 400 mm. A provision is required to hold the cylinder anywhere in between the end positions. Select the different components from the data tables given. Specify the ratings of the components in case, it is not available in the given data. Save Passage before moving to next question. Passage word limit: 500 words File size limit: 2 MB (JPG) Save Passage Select file Select file Select file Select file

Answer 1

→ Hydraulic circuit to operate cylinder. mieler cut chreuit is chosen to adjus the speed of extension t velvochon 15 per requirement It has two flow control valves. F. 4 F2 Tienced to control speed of extension F is used to control speed of retraction F -- Given Fertoend during extension = 15 kn FR: loof during mefraction: 9:5 KN VIE="Vou velocity during Exl-eristen trefraction 35mmin in 55 mlmin = 0.05833 mis, Too 09167 mi's |::rcke : 400 rp: Ca C. - Destan From given table on vane punup, it is seen that the pumps are ovollable Domy a maximum posuere of me bar, repice lets clock the design Ceylinder assuming poop Sun Ce lindore 1) selection of cylinder a) During Elangian giggles 20 of evindere 2x15590 · 0052131: 52.233 m Va ***POXIDE b) During rehrackan stroke edechime draweera De:10-1: FR 4% 9500 = 004116m ། ༑་། 71-757104 -41.568 mm Ferom the table top cylinder Agis selected Thae bowe drameler D-95mm : 00115m rod Homelev d: 45 mm =-0.045 2) selechon of pump 4 Fe 4x 1S000 a) proscere during extension: Pes A TTX 10 000) Pe: 89.95105 Filmz- 09.95 bar. ومن . לפור

0 091617 15.4616 FR 4 FR 4x9500 2 b) Discharge during extension Qe: Axte: TO?x ve -0-0052 x 0105839 to 5 007s2x 2.51698104 to 4:049 810-4 mals to 24.2991 atsimin c) Pressure during refraction = pe: (A-C) T1(02-12) (0.017526045 . 33.59x105 N/m2 = 33.59 bar. d) Drscharge during refratron Qr= (A-A) YR= TT (D?-12) (309520845?005533 te ini 600520:043*) x 0:0916" 1.649210-4 to 2.5919 810-4 mils Asimin - so discharge required 15 242991 etsimen and 20'95 bermi during extension + 15:55) szimin et 32-59 bera during retrochton From gluen vano pump..pump fs is selecled, it has discharge 39 atsimin at o bere ans its/min af 35 bar, 35 bits/min at no bar 3) selection of reservoir Capacity of reservoin should be more than three time the maximum discharge, capaerly D reserveix » 3*37.5 > 112.5 etsimin so reservoir meder Ta is selected. have capacity 250 ets 1) selecten of other component Mox: pressuro in system : 33.95 ban, Most Discharge in syslem: 24.2991 ts min. 15:55 !

sr NU 1 2 For these above value, following components are selected component Model Pressure Flow rate range. range Shrainer S 38 ets/min Pressure gauge PG2 6.40 bar. Relief valve R3 30°4 ats/min flow control valve F4 0-24 6 ets/min Direction control valve 38 êts/min check valve 210 bar 30.4 ets/min. 3 ५ Yobari no bar. 210 bar U 6 (2 ets/min Edpm
please give some positive rating.. i have less cf score..

Thank You So Much..