Question

QUESTION 6 15 marks In this question you have to write a C++ program to convert a date from one format to another. You have to write a complete program consisting of a main() function and a function called convertDate(). The function receives a string of characters representing a date in American format, for example December 29, 1953. The function has to convert this date to the international format. For example: If the string December 29, 1953 is received, the string that the function should return must be 29 December 1953 Use the following C++ skeleton: include <iostream> #include <string> using namespace std; string convertDate(...) // Add the code for the function here } [TURN OVER] 12 int main() { string americanDate; // Add the code for the main function here return 0; } The main() function should prompt the user to enter the string, then read the string and call function convertDate() to convert it to the required form. Hint 1: Below the question we list a number of stringmember functions you may need. Hint 2: Start the convertDate() function by determining the position of the first space character in the input. A number of stringmember functions to help you StringObject.size() StringObject. substr(startPos, length) StringObject.find(substring) StringObject.find(substring, startPos) StringObject.insert(insertPos, substring); StringObject.erase(startPos, length); StringObject.replace(startPos, length, substring); where startPos, lengthand insertPoSare of type int, and substringis of type string.

Answer 1

c++ code

#include <iostream>
#include <string>

using namespace std;

string convertDate(string americanDate)
{
int firstspacepos=0,firstcommapos=0;
for(int i=0; i<americanDate.length(); i++)
{
if(americanDate[i]==' ')
{
firstspacepos=i;
break;
}
}
for(int i=0; i<americanDate.length(); i++)
{
if(americanDate[i]==',')
firstcommapos=i;
}
string internationaldate="";
for(int i=firstspacepos+1; i<firstcommapos; i++)
{
internationaldate+=americanDate[i];
}
internationaldate+=" ";
for(int i=0; i<firstspacepos; i++)
{
internationaldate+=americanDate[i];
}
for(int i=firstcommapos+1; i<americanDate.length();i++)
{
internationaldate+=americanDate[i];
}
  
return internationaldate;
}

int main()
{
string americanDate;
cout<<"Enter american date: ";
getline(cin,americanDate);

cout<<"Converted date: ";
cout<<convertDate(americanDate)<<endl;
return 0;
}

Sample output

Enter american date: January 25, 1990                              

Converted date: 25 January 1990  

Enter american date: November 2, 1989                              

Converted date: 2 November 1989

Enter american date: March 08, 1996                                

Converted date: 08 March 1996