The α-particles with 6.7 MeV kinetic energy are directed into a
gold plate. The thickness of the gold plate is 3.4x10-7 m, the
number of cores per unit volume of the plate is 5.9x1028 cores / m
^ 3, and the number of α-particles hitting the gold plate per
second is 4.1x107.
a) Find the fraction of α-particles scattered between 30 ° and 60
°.
b) The window of an α-detector placed at a 45 ° deviation angle at
a distance of 15 cm from the point of collision of the bundle is 4
cm2. Find the number of α-particles coming to the detector for 30
minutes.





The α-particles with 6.7 MeV kinetic energy are directed into a gold plate. The thickness of...
A beam of 8 MeV α particles scatters from a gold foil of thickness 0.2 µm. (a) What fraction of the α particles is scattered between 1° and 2°?
Alpha particles of kinetic energy 6.4 MeV are incident at a rate
of 3.2 107 per second on a gold foil of thickness 3.2 10-6 m. A
circular detector of diameter 1.0 cm is placed 13 cm from the foil
at an angle of 30° with the direction of the incident alpha
particles. At what rate does the detector measure scattered alpha
particles? (The molar mass of gold is 197.0 g/mol and its density
is 19.3 g/cm3.)
Alpha particles of...
Alpha particles of kinetic energy 6.8 MeV are incident at a rate of 2.9 x 107 per second on an aluminum foil of thickness 2.9 x 10-6 m. A circular detector of diameter 1.0 cm is placed 14 cm from the foil at an angle of 30° with the direction of the incident alpha particles. At what rate does the detector measure scattered alpha particles? (The molar mass of aluminum is 27.0 g/mol and its density is 2.7 g/cm3.) s-1
Alpha particles of kinetic energy 6.8 MeV are incident at a rate of 2.9 x 107 per second on an aluminum foil of thickness 2.9 x 10-6 m. A circular detector of diameter 1.0 cm is placed 14 cm from the foil at an angle of 30° with the direction of the incident alpha particles. At what rate does the detector measure scattered alpha particles? (The molar mass of aluminum is 27.0 g/mol and its density is 2.7 g/cm3.) s-1
Each α particle in a beam of α particles has a kinetic energy of 7.1 MeV. Through what potential difference would you have to accelerate these α particles in order that they would have enough energy so that if one is fired head-on at a gold nucleus it could reach a point 1.5 10-14 m from the center of the nucleus?
Each α particle in a beam of α particles has a kinetic energy of 7.5 MeV. Through what potential difference would you have to accelerate these α particles in order that they would have enough energy so that if one is fired head-on at a gold nucleus it could reach a point 1.7 10-14 m from the center of the nucleus?
Each α particle in a beam of α particles has a kinetic energy of 5.6 MeV. Through what potential difference would you have to accelerate these α particles in order that they would have enough energy so that if one is fired head-on at a gold nucleus it could reach a point 1.9 10-14 m from the center of the nucleus?