A beam of 8 MeV α particles scatters from a gold foil of thickness 0.2 µm.
(a) What fraction of the α particles is scattered between 1° and 2°?
A beam of 8 MeV α particles scatters from a gold foil of thickness 0.2 µm....
The α-particles with 6.7 MeV kinetic energy are directed into a
gold plate. The thickness of the gold plate is 3.4x10-7 m, the
number of cores per unit volume of the plate is 5.9x1028 cores / m
^ 3, and the number of α-particles hitting the gold plate per
second is 4.1x107.
a) Find the fraction of α-particles scattered between 30 ° and 60
°.
b) The window of an α-detector placed at a 45 ° deviation angle at
a...
Alpha particles of kinetic energy 6.4 MeV are incident at a rate
of 3.2 107 per second on a gold foil of thickness 3.2 10-6 m. A
circular detector of diameter 1.0 cm is placed 13 cm from the foil
at an angle of 30° with the direction of the incident alpha
particles. At what rate does the detector measure scattered alpha
particles? (The molar mass of gold is 197.0 g/mol and its density
is 19.3 g/cm3.)
Alpha particles of...
+ 0/8 points Previous Answers Alpha particles of kinetic energy 4.80 MeV are scattered at 90° by a gold foil. (a) What is the impact parameter? 19.95 X fm (b) What is the minimum distance between alpha particles and gold nucleus? 68.14 xfm (c) Find the kinetic and potential energies at that minimum distance. K = 1.467 X Mev U= 3.333 x Mev
Each α particle in a beam of α particles has a kinetic energy of 7.1 MeV. Through what potential difference would you have to accelerate these α particles in order that they would have enough energy so that if one is fired head-on at a gold nucleus it could reach a point 1.5 10-14 m from the center of the nucleus?
Each α particle in a beam of α particles has a kinetic energy of 7.5 MeV. Through what potential difference would you have to accelerate these α particles in order that they would have enough energy so that if one is fired head-on at a gold nucleus it could reach a point 1.7 10-14 m from the center of the nucleus?
Each α particle in a beam of α particles has a kinetic energy of 5.6 MeV. Through what potential difference would you have to accelerate these α particles in order that they would have enough energy so that if one is fired head-on at a gold nucleus it could reach a point 1.9 10-14 m from the center of the nucleus?
A beam of 0.4 MeV y-rays with an intensity 108y-rays/cm-s is incident on thin foil of target material having thickness 0.2 cm. 95 % of photons pass through the foil without making any interactions. Total energy deposited in the foil is 1.5x10 MeV/cma-s. Determine attenuation and linear absorption coefficients of target material.
Protons of energy 4.7 MeV are incident on a copper foil of thickness 4.9 x 10-6 m. What fraction of the incident protons is scattered at the following angles? (The density of copper is 8.9 g/cm", and its molar mass is 63.5 g/mol. (a) greater than 90° 0.000026 (b) less than 5°
1 Rutherford Rutherford discovered the nucleus of the atom by firing α particles at gold foil. An a particle has a charge of q+2e and a mass of m 6.64 102 kg. A gold nucleus has charge of Q = +79e. You may ignore the motion of the gold nucleus in this problem +2e +79e Suppose an a particles is traveling directly toward a gold nucleus. If the speed of the a particle is 1.9-107 m/s when it is 1...
Alpha particles of kinetic energy 6.8 MeV are incident at a rate of 2.9 x 107 per second on an aluminum foil of thickness 2.9 x 10-6 m. A circular detector of diameter 1.0 cm is placed 14 cm from the foil at an angle of 30° with the direction of the incident alpha particles. At what rate does the detector measure scattered alpha particles? (The molar mass of aluminum is 27.0 g/mol and its density is 2.7 g/cm3.) s-1