Question

Part C Iron has a density of 7.86 g/cm (1 cm = 1 mL). Calculate the volume (in dL) of a piece of iron having a mass of 4.25 kg . Note that the density is provided in different units of volume and mass than the desired units of volume (dL) and the given units of mass (kg). You will need to express the density in kg/dL (1 cm = 1 mL) before calculating the volume for the piece of iron. Express your answer to three significant figures. View Available Hint(s) IVO AE h ? volume = 54.1 dL Submit Previous Answers X Incorrect; Try Again; 3 attempts remaining Your answer is off by a factor of 10". You may have used an incorrect conversion factor when converting from g to kg or from cm' to L. The units of cm are equivalent to i DL the units of mL (1 cm = 1 mL). Converting from mL to dL involves using the conversion factor of 100 mL Finally, convert the units of grams to kilograms using the 1 kg conversion factor of 1000 g You may need to review Conversion Between g and kg.

Answer 1

Sol:maas of iron piece=4.25kg

=4.25x1000g (1kg=1000g)

=4250g

Density of iron =7.86g/cm3

=7.86g/mL(1cm3=1mL)

=7.86×100g/dL(1dL=100mL)

=786g/dL

Density = mass/volume

Volume =mass/density

=4250g/786g/dL=5.41dL

Hence the correct answer is 5.41dL.