Question

Find all solutions to the equation x' +27 = 0 over the Complex Numbers. Do all parts (a)-(d): (a) Graph complex number -27+0.i as a vector in trigonometric form (b) Use De Moivre's Theorem to find one cube root of -27 (c) Graph all three solutions as vectors (in trigonometric form) on the xy-plane (d) Lastly, convert each solution from trigonometric form reise to standard form a +bi

can I get the answer ever each steps

Answer 1

Solution's -97 +0.1 2) +201 -1 +0.1] 22 ICOD 11 + i sin t] a 1 27 I cip Imagerary Axix kt -2.7 Real Atix. x =-27+o.i n=t-37+0.9)/3 31-17 0.1% az 3 [cop 11+ i sin 1]%3 n = from Theorem De moiver's 3 [ cip II N = Noc 31 / 4 + 1 In = 3+: 383 2.

@ Given Equation in a cigo form • 3 Icing >> 3% copy tisins] =) + 3 31 h 3+1 3 3 2 The and 2