Question

Find all solutions to the equation x' +27 = 0 over the Complex Numbers. Do all parts (a)-(d): (a) Graph complex number -27+0.i as a vector in trigonometric form (b) Use De Moivre's Theorem to find one cube root of -27 (c) Graph all three solutions as vectors (in trigonometric form) on the xy-plane (d) Lastly, convert each solution from trigonometric form reise to standard form a +bi

Answer 1

Solution -97 +0,1 2) + +201 -1 +0.1] 221c0p 11 +ision] > 97 [ cip 12 Imagerary Axix kt -27 Real Axix. 6 N 22--27+0.1 [-27+0.8) 3 43 31-1 +0.17% 3Ľ cop tot i sino X 7 Sin 1] som De moiver's Theorem = 3 [ cip] n = ༧ 312+ i 3 2 ka 3gp In = 3+1 383 2.

form In r.cigo @ Given Equation 3 [cip >> » 31 copy tising 31+ +103] , 3+73 v3 2 ? The and a