Question

The maximum velocity of a particle executing simple harmonic motion with amplitude 7.0 mm is 4.4 m/s. The period of oscillation is?

Answer 1

The maximum velocity of a particle executing simple harmonic motion with amplitude 7.0 mm is 4.4 m/s. The displacement of a partiele in S.H.M written as, can be x = A Cos (w + + 0) 20 20 3 t A = amplitude. = angaular frequency = time . phage angle. = displacement. = o velocity V = of the partiele will be, A cos (ut + 0) -%)] AW Sin (wt +0) AW Sin caut +0) da dt d dt [ > V = V 1. velocity v will be maximum , then, sin (uit + o) and, V = AW (-1) = +AW

maximum velocity is, The V = 4.4 m/s. AW = 4.4 m/s → -3 (7 x 10 m m ) X W > 4.4 m/s 4.4 m/s → 7 x 10 m > 3 628.57 oscillation of the The period of partiele i$, 20 T = 2 X 3.14 628.575 T = 9.991 X 10 T = 0.009991 sec (Answer)