Question

A 6.00-kg block is in contact with a 4.00-kg block on a horizontal frictionless surface as shown
in the figure. The 6.00-kg block is being pushed by a horizontal 20.0-N force as shown.

a. What is the acceleration of the blocks?
b. What is the magnitude of the force of the 6.00-kg block on the 4.00-kg block?
c. What is the magnitude of the force of the 4.00-kg block on the 6.00-kg block?
d. What is the net force on the 6.00-kg block?
e. What is the net force on the 4.00-kg block?

20.0 N 6.00 kg 4.00 kg

Answer 1

Answer 20-0N 6.00 Kg 4.00 kg. la) woh acceleration of blocks. 20 6+4 - 2 Fest EM m/sec as (6) F-B-D. ef blocks 20.00 -N2 4 kg 6.00 kg Tig (2) fig(i) where Ni = N2 by newton's law enfig ☺ 20 - N₂=ma 20-682-N2 N2=EN the 600 kg blocks on the i e. magnitude of the force of 4.00 kg blocks = N1= 8N blocks on the N = 4X2=8N the force of ♡ av Similarly magnitude of the 4 kg m blocks. Gookg = 20 - 8 =12 on booky blocks, Farming = 20-N2 & Net force -Izny the Are (d) Fanny Na Anna kg 4.00 blocke Fuookg = Ni = 8N on Net force (e)