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A 4.7 kg block is being pushed across a frictionless horizontal surface by a horizontal force....

A 4.7 kg block is being pushed across a frictionless horizontal surface by a horizontal force. The block accelerates at 3.8 m/s2. What is the magnitude of the normal force the surface exerts on the block? Express your answer in newtons and round to one decimal place.

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Answer #1

Given:

m=4.7\ \text{kg}

Since it is a horizontal table, the normal force is equal to the weight of the block. That is,

R=mg\\ =4.7\times9.8\ \text{N}\\ =46\ \text N

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