Question

1) Use your data to calculate the initial ball velocity for each of the HORIZONTAL launcher settings:

Part 2 - Initial Ball Velocity Vertical Distance Small Range Trial 1 Total Horizontal Distance (cm) 161.4 Launch Velocities (m/s) 3.544590954 Time of Flight (cm) 0.454313 1.604m Trial 2 161.5 3.549371761 3.544590954 Trial 3 Trial 4 1.604m 1.604m 1.604m 161 159.6 Avg = 160.87 0.454008 0.453294 0.452748 Avg = 0.453295 3.514444366 Avg = 3.53824950 Medium Range Trial 1 193.3 1.604m 4.243401511 0.453178 193.1 1.604m 4.234417344 0.453416 Trial 2 Trial 3 Trial 4 193.6 1.604m 4.244842516 0.454214 1.604m 192.4 Avg = 193.1 4.22012154 Avg = 4.23308943 0.453801 Avg = 0.453652 Long Range Trial 1 219.1 1.604m 4.777830865 0.453435 Trial 2 219 1.604m 217.6 Trial 3 Trial 4 1.604m 1.604m 4.777374355 4.755111745 4.75104523 Avg = 4.77090620 0.454402 0.453782 0.45368 Avg = 0.453824 218.6 Avg = 218.5

Answer 1

como es un lanzamiento horizontal, la velocidad inicial es solo horizontal, que es constante en todo el movimiento y solo varía en el eje-Y. Por lo tanto, puede calcular el valor inicial por.

$x=v_{0x}t_f$

clearing the variable initial velocity, we have

VOT ti

then, taking the average values of the distance X and time of flight, the initial velocity for each range is:

1. Small Range

$v_{0x}=\frac{x}{t_f}=\frac{1.6087m}{0.453s}=3.551m/s$

2. Medium Range

$v_{0x}=\frac{x}{t_f}=\frac{1.931m}{0.453s}=4.263m/s$

3. Long Range

$v_{0x}=\frac{x}{t_f}=\frac{2.185m}{0.453s}=4.823m/s$