Question

given the information

1 Common conversions: 1 hr = 3600 s 1 N = 1 kg*m/s2 1 J = 1 N*m = 1 kg*m-/s2 1 W = 1 J/s = 0.738 ft-lb/s 1 hr = 550 ft-lb/s = 746 W 1 kW*h = 3.60x106J 1 eV = 1.602x10-19 J 1 C = 1 A's 1 V = 1 J/C 12 = 1 VIA 1 A = 1 C/s 1 T = 1 N/A*m 1 Wb = 1 T*m 0°C = 273.15 K = 32°F 1 revolution = 360 = 2TT rad 1 radian = 57.3* = 0.159 rey 1 Hz = 1/s 1 Pa = 1 N/m2 1 atm = 1.01x106 Pa =14.7 lb/in? 1000 L = 1 m = 35.3 ft = 264 gal 1 g/cm = 1000 kg/m 1 cal = 3.969x10 Btu = 4.1860 J 1 Cal = 1000 cal 1 mol = 6.02x102 particles Common constants: 9.81 m/s2 = gravity on Earth's surface 343 m/s = speed of sound (air @ 20°C) 1440 m/s = speed of sound (water @ 20°C) 1.21 kg/m = air density (20°C, 1 atm) 998 kg/m = water density (20°C, 1 atm) 1 atm = 1.01 x 105 Pa 3 x 10 m/s = c = speed of light (vacuum) 1.661x10-27 kg = p = atomic mass unit Specific Heats: Cice = 2040J/(kg °C) Cwater = 4186J/(kg * °C) Cwater vapor 1996J/(kg • °C) Heat of Transformation for H2O: Lv = 539 cal/g = 40.7 kJ/mol = 2256 kJ/kg Le = 79.5 cal/g = 6.01 kJ/mol = 334 kJ/kg Stefan-Boltzmann constant = o = 5.6703x10 W/(m2*K) Gas constant = R = 8.31 J/(mol*K) Avogadro's number = NA = 6.02x1023 mol-1 Boltzmann constant = ka = R/NA = 1.38x10-23 J

answer: clearly and correct

Answer 1

Solution:

Given,

height of cylinder iceberg

h = 210m

radius of cylinder iceberg

r = 470m

density of sea water

PI 1030kg/m

The iceberg extends 22.0 m above the ocean. Thus, the height of iceberg below the ocean is given by,

h = h - 22.0= 210 - 22.0 = 188m

Let the density of ice be $\rho_{s}$ .

Volume of immersed part of the iceberg is given by

   ....... (1)

V = ardh = X 4702 x 188

Total volume of the iceberg is given by

   ............ (2)

V = ardh = X 4702 x 210

By the principle of floatation,

Ps V PI

  

a X 4702 x 188 À X 4702 x 210 ps 1030

  

188 210 Ps 1030

188 Ps x 1030 = 922.10kg/m* 210

The density of the iceberg is

922.10kg/m