Question

(a) A narrow beam of light containing range (610 nm) and yellow (tom) wavelengths goes from polystyrene to ar, striking the surface at a 21.5 incident angle. What is the angle (in degrees) between the colors when they emerge? (6) How far would they have to travel (in m) to be separated by 1.00mm?

Answer 1

A)

HERE we have given that,

Angle = 23.5 °

Refractive index of polystyrene as,

For orange colour = 1.490

For yellow color = 1.493

So that the angle of their emergence will be,

From snells law we have,

n1Sin(theta1) = n2Sin(theta2)

So that, angle between the colors when they emerge will be,

Delta theta = 36.5363 - 35.4510

= arcSin(1.493×Sin23.5°) - arcSin(1.490Sin23.5)

Hence,

Angle = 0.08525 °

b)

And the distance for them to travell to seperation of 1mm we will have,

1/Sin36.4510- 1/Sin(36.5363) = 3.3837 m = 3.38 m

So that they have to travel

Distance = Cos36.5363) × 3.3837 = 2.718 m