Question

Two converging lenses having focal lengths off, = 11.3 cm and f, - 20.0 cm are placed d = 50.0 cm apart, as shown in the figure below. The final image is to be located between the lenses, at the position x = 33.3 cm Indicated. 12 Object Final image (5) How far (in cm) to the left of the first lens should the object be positioned? cm (b) What is the overall magnification of the system? (c) is the final image upright or werted? vorig Inverted Need Help?

Answer 1

<d=50och Ere x=33.300 v= sos 0418-66n- Image =log Image pooltion from and good beng. As the final image to belid the 2nd len, it will beristul 5%; f2= zoom by any formula to ta = // - 3/5 te = 120 t u = 30 + 3 t 1=-100 ;u=-100cm Object location U=400=x-9cm. for and leng = liu ЧИ 11

The above object will be the image for the lot lept so mage location by ppt lens U = 50- 100 =/49 cm 24.1n This image will beocal and mverted How by leng termula forest leno:- u=+41cm, f=11.30m. to ta=Y4=) # = 73 t = tis - 5 ta u Z-15.6cm by The objeet Storeld be blaced =15.6 cm lettfrom - 0.064 ppt leno. = 11 (b magnification - ulttoal Image) ūCrital object) =orm &m mi= magnification by lot - la C-U2 ) M2= land 16:7 156 - 9 41x16:7 15-6x9 4.80 Ano o final image is inverted, = 8167 and option incorrect