Question

mc Lems Auad imaye fey

Answer 1

solutics > di = image formed by 4 fi Iz tual 19cm soom & Lidlay image 5 40cm Given that: fi = 20cm &focal length of 4? faaloom & focal tength of L2 ? d = 40cm & separatin between Li&L₂3 V2=19cm & Distance of image formed by L2} U = Distance of object from 4 va Distance of image formed by 4 from P U2 = Distane of object from pa for Lz. How Ist of all we will find the value of 4₂. We know the tense formula - How let II. o u

Her v=V2=19cm f=f2 = 10cm U= 4₂ (To be find) & Thus tt & r. 122-19cm foc locomo - 19 - => tate to to e 29 Pit is 'scalar? 7 14 =-6.sscm] This is location of object for Lz. from figuse it is clear that U2=-6.Ssom docate di from Lz. & Taking 141 because Now Vi=d-1421 19=40cm - 6.55cm v = 33.45cm How by tense fermula- I-tat 1 41 -

33.4 3 = has to 7 -3545 zo 3 33AS 20 x 33.45 20-33.45 669 u= 13.45 4 -- 49. 74 cm This 49.74 cm should be the This is answer for far to the left the first sense object positioned. past @.

- 6 The magnification for 4 m = 1 33.45 mi 99.74 W 233.45 cm u=-49, 76cm) mi 2-0.6725 The magnification for tz VUUUUUUU m₂ - V2 mas uz -19 M2=-6.55 1m2=2.900 $$ $ $ 330d U Hence overall magnification ma mi. Ma m= – 0.6725 X 2.9 Im=-1.95 This is value of overall magnification, o since overall magnification in is negative thesefase final image is inverted,
ANSWER (a)u₁=49.74cm

(b)m=-1.95

(c) final image is inverted