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C 13 , = 6.0V 4. Determine the each of the currents in each path, and the voltages across each resistor. Ε 24.0V b d 0.10 Ω R

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27-V oolo I D 20 ABV T R? 0.50 40 13 0.20 78 I 36V 6V 6os At KCL Iz = I1+I2 Loop I 24-48 = I, (5+0.10+20+40 to.5o) -I,C 40.5equation 4 ④ solved I = -8.05 (direction reverse) [I 8.050 I2 -12.44 A ( direction reverse) I2 = 12:44 Ia = I, t Iz Iz -20.49

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