Question

A generator rotates at \(91 \mathrm{~Hz}\) in a magnetic field of \(0.025 \mathrm{~T}\). It has 950 turns and produces an \(\mathrm{rms}\) voltage of \(140 \mathrm{~V}\) and an \(\mathrm{rms}\) current of \(40.0 \mathrm{~A}\).

Part A 

What is the peak current produced?

Express your answer to three significast figures and include the appropriate units.

$$ I_{\text {peak }}=56.6 \mathrm{~A} $$

Part B

What is the area of each turn of the coil?

Express your answer to two significant figures and include the appropriate units.

Answer 1

Answer Given; fa 91 Hz. 0.025 T. NE 950 turns. 140 V Vrms Irma 40 A Thus; 21f 2x 3.14% 91 571.48 rad's Peak current T - peak Ioms x 2 2 Ipeak 40x52 56.6A b) Area of coil Peak voltage ; Xpeak Nims 521 198 V In an generator; Vpeak - 'N B Aw & Area of coil Npeak NB w A 198 950 X-0.025 x 571.48 0.014 m