
8. A 90kg basketball player is traveling at a velocity of 3.7m/s. What is her momentum...
7. A 58 kg runner is traveling at a velocity of 5 m/s. What is her momentum (in Ns)?
A basketball player drops a 0.60 kg basketball vertically so that it is traveling 6.0 m/s when it reaches the floor. The ball rebounds upward at a speed of 4.2 m/s. (a) Determine the magnitude and direction of the ball’s change in momentum. (b) Determine the average net force that the floor exerts on the ball if the collision lasts 0.12s.
Here's a basketball problem: A 81.6 kg basketball player is running in the positive direction at 7.8 m/s. She is met head-on by a 98.4 kg player traveling at 5.9 m/s toward her. If the 98.4 kg player is knocked backwards at 2.6 m/s, what is the resulting velocity of the 81.6 kg player?
A basketball player drops a 0.60-kg basketball vertically so that it is traveling at 6.3 m/s when it reaches the floor. The ball rebounds upward at a speed of 4.7 m/s. B.) Determine the average net force that the floor exerts on the ball if the collision lasts 0.12 s. Express your answer to two significant figures and include the appropriate units. NSonB =
A 90kg hockey player is skating with the puck at 25m/s(north), When he collides with a second hockey player, this one with a mass of 95kg, who is skating 12m/s (west). The two players get tangled up on impact and move together. What is the velocity (magnitude and direction) of the two players after impact?!
1. A 10,000 KG truck is traveling at +20 m/s. What would
happen to the momentum of the truck if it increases in velocity in
the same direction?
2. A 120 KG rugby player is running toward another player at 5
m/s. How much force needs to be applied over one second in order to
bring him to a stop?
3. if the acceleration of an object decreases, what happens to
the inertia?
A 10,000kg truck is traveling at +20m/s....
The momentum of a ball traveling with velocity v is p. What should be its velocity for it to have momentum 4p? A. 4v B. v C. 0.5 v D. 2v
What velocity must a 1340 kg car have in order to have the same momentum as a 2680 kg truck traveling at a velocity of 15 m/s to the west?
I've tried using conservation of momentum to get -14.28 I then used to that find the new velocity of the player which i got to be 3.04 but it says it's wrong.
A player shoots a basketball as shown, below. Points Q and S are at the same height and R is at the top of the trajectory. All statements refer to the basketball. Coordinate system: the x-axis is horizontal and points to the right, the y-axis is vertical and points up. (Neglect air friction.) D The acceleration at S is... that at Q. D The y-component of the velocity at Q is... at S D The x-component of the velocity at...