Determine the mass (g) of aluminum deposited in an electrolytic cell using a current of 0.750...

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Determine the mass (g) of aluminum deposited in an electrolytic cell using a current of 0.750...

Determine the mass (g) of aluminum deposited in an electrolytic cell using a current of 0.750 A for 1.2 hour (1 hour = 3,600 s)

Al³⁺(aq) + 3e^- ⟶ Al(s)

A. 0.000839 g

B. 2.20 g

C. 0.302 g

D. 0.625 g

E. 0.906 g

science chemistry

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Answer 1

Answer #1

Al3+ + 3 e Alis) Current CI) = Charge(&) Time (t) Current = 0. 750 A Time 1.2 hour 1.2 (360os) = 432os Charge (6.750 A) (4320

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