1. Yes the compound is meso and plane of symmetry is shown in figure

Meso compounds are those that have at least 2 asymmeteic carbon ( those carbon with all 4 subatituents to be different ). But both 2 asymmnetric carbon have same groups as one another ( as in this question). There must be a plane of symmetry passing through the molecule or the configuration of bothe asymmeteic carbon should be different.
And since as in the given question there are 2 assymeteic carbons and a plane passing through the molecule so it is meso compound.
Ques 2. Isomers are shown below :
Stereoisomers are those compound which have same molecular formula but different arrangement of atoms in space ( the position of atoms can be changed between the following positions: on plane, above plane or below plane). This movement constitute stereoisomer.
In stereoisomer the R/S configuration changes .
The configuratikn can be given as per CIP rule which is on the basis of atomic mass.
▪︎Higher the atomic mass more will be its priority.
▪︎ if while moving from 1st priority to 2nd and then to 3rd the direction of movement is clockwise then configuration is R. But if the direction is anticlockwise then configuration is S. But this is valid if 4th priority group is below the plane.
▪︎ if 4th priority group is above the plane then configuration reverses. I.e., the clockwise direction will now give S configuration and anticlockwise movement will now give R configuration.
Thus 3 isomer are as shown below with
•1 isomer both Asymmetric carbon have S configuation.
•the 2nd isomer has both carbons R configuration
•and in 3rd isomer there is 1R and 1 S configured carbon ( which is meso).

Relate each two of the three (or four) structures above with whether they are enantiomers or...
Please solve it clear , in first box in the question *first
image* what should I write , I don't understand can you do table in
paper and solve it in clear Hand write it's follow the next image
read then & ,thankyooou?????
Relate each two of the three (or four) structures above with whether they are enantiomers or diastereomers. USE THE NUMBERS MENTIONNED IN THE BOXES ABOVE TO RELATE BETWEEN THEM. (3 points for each relation, any additional relation...
please solve them clear & be sure thank you .
1. (21 points) Is the following compound a meso-compound? If yes, show it in 3D in the box below using wedged and dashed bonds to indicate the substituent bond direction and draw the internal mirror plane of symmetry (if any). (3 points) HOOC-CHOH-CHOH-COOH Draw the 3D structures of the stereoisomers of the compound above. Use wedged and dashed bonds to indicate the substituent bond direction in each stereoisomer. [Hint: if...
3B) Draw the constitutional isomers of trimethylcyclopropane as
skeletal structures.
3C) For each constitutional isomer you drew in part (a), draw
any stereoisomers of that structure, explicitly showing
stereochemistry with dash/wedge bonds. Use skeletal structures.
2. This molecule has a ring strain of 70 kl/mol. Circle which type of strain is most important, and explain why you circledit: Angle torsional steric 3. Only one stereoisomer of this compound is stable - draw the relative stereochemistry at the ring Junction with...
7. The structures of three nutritionally important vitamins are shown below. Use these structures to answer the following questions. Vitamin A (retinol) Vitamin B3 Vitamin K3 TOH a. Which of the vitamins is the most polar? Explain your reasoning in 1-2 sentences. (3 points) b. How many polar bonds are there in the structure you chose in part A? on the structure above, draw arrows pointing to each polar bond. (5 points) c. What is the chemical formula of vitamin...
Discussion Questions: 1. a) Carefully draw a three-dimensional structure of each stereoisomer of stilbene dibromide. Do not include any identical structures. b) Identify the enantiomeric pair, and identify one pair of structures that are diastereomers. 2. Give careful stereo-drawings representing the complete mechanism for the reaction of cis-stilbene with bromine. Remember to show the two different modes of anti-attack that are possible, depending on whether you add the bromine from above to the left-hand or the right-hand carbon of the...
4. Absolute Configuration and R/S Sequence Rules. In 3 you constructed models with two stereocenters that represented 4 stereoisomers. 2,3-Dibromobutanoic acid exemplifies such a compound, Make models for the isomers of this compound. a. Draw solid/dashed-wedge structures for the 4 possible stereoisomers and label the enantiomers and diastereomers. b. Specify the sequence priority for the substituents on carbon-2 and carbon-3. Label each structure with the proper R/S notation in the drawings above, for example (2R, 35). d. Draw Newman projections...
3. Diastereomers and Meso Forms. When a molecule has two or more stereogenic centers, stereoisomers that are not mirror images can exist; these are called diastereoisomers. Within this general class, there are special types of stereoisomers that are always optically inactive and are called meso forms. Construct a model with four different colored balls about a carbon center. Construct another identical to the first and verify this by the superimposition test. Now remove the same colored balls, blue (C from...
Analyze each pair of compounds structures represent. Your cho cach pair of compounds below. Identify which class of isomers each pair of s represent. Your choices are: (i) constitutional, (ii) conformational, (iii) omers, (iv) diastereomer or (v) identical (non-isomers). Only one label for each pair should be used. For each case show work (drawings, (R)/(S), rotation of bonds, chair- "ps, etc) which led you to each answer for the pairs below. Any differences of answers between you and your peers...
1. (2 points each) Draw the chemical structures of the following two compounds. iodoform 71-butanal 2. (2 points) Circle the compound that will give a positive result in the iodoform test. (a) acetophenone b) cyclopentanone c) isobutanol d) n-heptanal 3. (3 points) Convert the following molecule to a Fisher projection. OH | H Convert to a Fisher Projection H DH 1 OHHH HAH HEBH 4. (2 points) Circle the correct name of the following structure. ph a) (meso)-hydrobenzoin H -OH...
A. Enantiomers: Certain substances have the unique property of rotating the plane of plane-polarized light. Such light rotation is detectable with the aid of a polarimeter. In order for a molecule to be optically active it must be chiral. Chiral objects lack a plane of symmetry and are non-superimposable on their mirror images. A sp?- hybridized carbon atom can fulfill these requirements if all four of its substituents are different. 1. Methane a) Prepare a methane molecule and then substitute...