Question

Two large parallel plates have been oppositely charged. There is a uniform electric field ~ E present between the plates, as shown in the figure. A proton, with mass mp, is released from the positive plate at the same moment as an electron, with mass me, is released from the negative plate. Ignore the force that the two charges exert on each other. What fraction of the way to the negative plate has the proton moved by the time the electron passes it?

Annotation 2020-08-11 174410.png

Answer 1

proton Positive Plate Negative 190 Plate . let d be the separation blo the hoo plates charge de =46x10 9.1x10 moss of ea mass of e on e- = -31 -d Me kg. x 16 27 rug. 1.66 x 10 тр force on é E me QE acceleration on the è QE initial velocity of é = 0 let time laiken the é to cover the distance d =t. Equ. Of molion is S = ut + tat? > d oxt + 1.2E t2 me t2 a med 2 E t samed qE ď (d'ed) in the Now let the proton travels a dislonce time 't . force on prolon Acceleration of porolon - 2E E & initial me. velocity=0 Now $ ut & O + tat² 1. QE 2 med mp 26

1.66x 10-20 -31 d = me .d 9.lxo mp d'= 0.00054 d d = (5 48x10-4 4)d ar [ď = (0.054% el The distance travelled by prolon is 0.00054 Himos of the bolal separation blew the plates.