Question

(python)

[30] Implement exception handling with ValueError here in the following code: There are three blanks you need to fill in. Write the answers in the space given for you. class Area: def __init__(self): self.x = 0 def setX(self n): if n<=0: else: self.x = n #main code a = Areal) inputValue = int(input("Enter a Value that is greater than 0")) a.setX(inputValue) print("Invalid Input Value Entered")

Answer 1

input code:

''make a class Area' class Area: "'constructor' def _init__(self): self.x=0 ''set x method'' def setx(self ,n): if n<-0: raise ValueError else: self.x=n ''try catch block'' try: '''make object' a-Area() ''take user input inputvalue=int(input("Enter a value that is grater than 0:")) "''set x'' a. setx(inputvalue) 'except for handle a exceptions''' except valueError: ''print value'". print("Invalid Input Value Entered")

output:

Enter a value that is grater than 0:-4 Invalid Input Value Entered ... Program finished with exit code 0 Press ENTER to exit console. I

code:

'''make a class Area'''
class Area:
'''constructor'''
def __init__(self):
self.x=0
  
'''set x method'''
def setX(self,n):
if n<-0:
raise ValueError
else:
self.x=n

'''try catch block'''   
try:
'''make object'''
a=Area()
'''take user input'''
inputValue=int(input("Enter a Value that is grater than 0:"))
'''set x'''
a.setX(inputValue)
'''except for handle a exceptions'''
except ValueError:
'''print value'''
print("Invalid Input Value Entered")